1.5x^2-92x+640=0

Solution for 1.5x^2-92x+640=0 equation:

1.5x^2-92x+640=0

a = 1.5; b = -92; c = +640;
Δ = b2-4ac
Δ = -922-4·1.5·640
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-68}{2*1.5}=\frac{24}{3}
=8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+68}{2*1.5}=\frac{160}{3}
=53+1/3
$